3.6.48 \(\int \cot ^{\frac {9}{2}}(c+d x) (a+i a \tan (c+d x))^{5/2} (A+B \tan (c+d x)) \, dx\) [548]
Optimal. Leaf size=251 \[ \frac {(4-4 i) a^{5/2} (A-i B) \tanh ^{-1}\left (\frac {(1+i) \sqrt {a} \sqrt {\tan (c+d x)}}{\sqrt {a+i a \tan (c+d x)}}\right ) \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}}{d}+\frac {4 a^2 (130 i A+133 B) \sqrt {\cot (c+d x)} \sqrt {a+i a \tan (c+d x)}}{105 d}+\frac {2 a^2 (80 A-77 i B) \cot ^{\frac {3}{2}}(c+d x) \sqrt {a+i a \tan (c+d x)}}{105 d}-\frac {2 a^2 (10 i A+7 B) \cot ^{\frac {5}{2}}(c+d x) \sqrt {a+i a \tan (c+d x)}}{35 d}-\frac {2 a A \cot ^{\frac {7}{2}}(c+d x) (a+i a \tan (c+d x))^{3/2}}{7 d} \]
[Out]
(4-4*I)*a^(5/2)*(A-I*B)*arctanh((1+I)*a^(1/2)*tan(d*x+c)^(1/2)/(a+I*a*tan(d*x+c))^(1/2))*cot(d*x+c)^(1/2)*tan(
d*x+c)^(1/2)/d+2/105*a^2*(80*A-77*I*B)*cot(d*x+c)^(3/2)*(a+I*a*tan(d*x+c))^(1/2)/d-2/35*a^2*(10*I*A+7*B)*cot(d
*x+c)^(5/2)*(a+I*a*tan(d*x+c))^(1/2)/d+4/105*a^2*(130*I*A+133*B)*cot(d*x+c)^(1/2)*(a+I*a*tan(d*x+c))^(1/2)/d-2
/7*a*A*cot(d*x+c)^(7/2)*(a+I*a*tan(d*x+c))^(3/2)/d
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Rubi [A]
time = 0.60, antiderivative size = 251, normalized size of antiderivative = 1.00, number of steps
used = 8, number of rules used = 6, integrand size = 38, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {4326, 3674,
3679, 12, 3625, 211} \begin {gather*} \frac {(4-4 i) a^{5/2} (A-i B) \sqrt {\tan (c+d x)} \sqrt {\cot (c+d x)} \tanh ^{-1}\left (\frac {(1+i) \sqrt {a} \sqrt {\tan (c+d x)}}{\sqrt {a+i a \tan (c+d x)}}\right )}{d}-\frac {2 a^2 (7 B+10 i A) \cot ^{\frac {5}{2}}(c+d x) \sqrt {a+i a \tan (c+d x)}}{35 d}+\frac {2 a^2 (80 A-77 i B) \cot ^{\frac {3}{2}}(c+d x) \sqrt {a+i a \tan (c+d x)}}{105 d}+\frac {4 a^2 (133 B+130 i A) \sqrt {\cot (c+d x)} \sqrt {a+i a \tan (c+d x)}}{105 d}-\frac {2 a A \cot ^{\frac {7}{2}}(c+d x) (a+i a \tan (c+d x))^{3/2}}{7 d} \end {gather*}
Antiderivative was successfully verified.
[In]
Int[Cot[c + d*x]^(9/2)*(a + I*a*Tan[c + d*x])^(5/2)*(A + B*Tan[c + d*x]),x]
[Out]
((4 - 4*I)*a^(5/2)*(A - I*B)*ArcTanh[((1 + I)*Sqrt[a]*Sqrt[Tan[c + d*x]])/Sqrt[a + I*a*Tan[c + d*x]]]*Sqrt[Cot
[c + d*x]]*Sqrt[Tan[c + d*x]])/d + (4*a^2*((130*I)*A + 133*B)*Sqrt[Cot[c + d*x]]*Sqrt[a + I*a*Tan[c + d*x]])/(
105*d) + (2*a^2*(80*A - (77*I)*B)*Cot[c + d*x]^(3/2)*Sqrt[a + I*a*Tan[c + d*x]])/(105*d) - (2*a^2*((10*I)*A +
7*B)*Cot[c + d*x]^(5/2)*Sqrt[a + I*a*Tan[c + d*x]])/(35*d) - (2*a*A*Cot[c + d*x]^(7/2)*(a + I*a*Tan[c + d*x])^
(3/2))/(7*d)
Rule 12
Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] && !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]
Rule 211
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/Rt[a/b, 2]], x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]
Rule 3625
Int[Sqrt[(a_) + (b_.)*tan[(e_.) + (f_.)*(x_)]]/Sqrt[(c_.) + (d_.)*tan[(e_.) + (f_.)*(x_)]], x_Symbol] :> Dist[
-2*a*(b/f), Subst[Int[1/(a*c - b*d - 2*a^2*x^2), x], x, Sqrt[c + d*Tan[e + f*x]]/Sqrt[a + b*Tan[e + f*x]]], x]
/; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 + b^2, 0] && NeQ[c^2 + d^2, 0]
Rule 3674
Int[((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((A_.) + (B_.)*tan[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*tan[(e_
.) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp[(-a^2)*(B*c - A*d)*(a + b*Tan[e + f*x])^(m - 1)*((c + d*Tan[e + f*x]
)^(n + 1)/(d*f*(b*c + a*d)*(n + 1))), x] - Dist[a/(d*(b*c + a*d)*(n + 1)), Int[(a + b*Tan[e + f*x])^(m - 1)*(c
+ d*Tan[e + f*x])^(n + 1)*Simp[A*b*d*(m - n - 2) - B*(b*c*(m - 1) + a*d*(n + 1)) + (a*A*d*(m + n) - B*(a*c*(m
- 1) + b*d*(n + 1)))*Tan[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B}, x] && NeQ[b*c - a*d, 0] && E
qQ[a^2 + b^2, 0] && GtQ[m, 1] && LtQ[n, -1]
Rule 3679
Int[((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((A_.) + (B_.)*tan[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*tan[(e_
.) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp[(A*d - B*c)*(a + b*Tan[e + f*x])^m*((c + d*Tan[e + f*x])^(n + 1)/(f*
(n + 1)*(c^2 + d^2))), x] - Dist[1/(a*(n + 1)*(c^2 + d^2)), Int[(a + b*Tan[e + f*x])^m*(c + d*Tan[e + f*x])^(n
+ 1)*Simp[A*(b*d*m - a*c*(n + 1)) - B*(b*c*m + a*d*(n + 1)) - a*(B*c - A*d)*(m + n + 1)*Tan[e + f*x], x], x],
x] /; FreeQ[{a, b, c, d, e, f, A, B, m}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 + b^2, 0] && LtQ[n, -1]
Rule 4326
Int[(cot[(a_.) + (b_.)*(x_)]*(c_.))^(m_.)*(u_), x_Symbol] :> Dist[(c*Cot[a + b*x])^m*(c*Tan[a + b*x])^m, Int[A
ctivateTrig[u]/(c*Tan[a + b*x])^m, x], x] /; FreeQ[{a, b, c, m}, x] && !IntegerQ[m] && KnownTangentIntegrandQ
[u, x]
Rubi steps
\begin {align*} \int \cot ^{\frac {9}{2}}(c+d x) (a+i a \tan (c+d x))^{5/2} (A+B \tan (c+d x)) \, dx &=\left (\sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \int \frac {(a+i a \tan (c+d x))^{5/2} (A+B \tan (c+d x))}{\tan ^{\frac {9}{2}}(c+d x)} \, dx\\ &=-\frac {2 a A \cot ^{\frac {7}{2}}(c+d x) (a+i a \tan (c+d x))^{3/2}}{7 d}+\frac {1}{7} \left (2 \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \int \frac {(a+i a \tan (c+d x))^{3/2} \left (\frac {1}{2} a (10 i A+7 B)-\frac {1}{2} a (4 A-7 i B) \tan (c+d x)\right )}{\tan ^{\frac {7}{2}}(c+d x)} \, dx\\ &=-\frac {2 a^2 (10 i A+7 B) \cot ^{\frac {5}{2}}(c+d x) \sqrt {a+i a \tan (c+d x)}}{35 d}-\frac {2 a A \cot ^{\frac {7}{2}}(c+d x) (a+i a \tan (c+d x))^{3/2}}{7 d}+\frac {1}{35} \left (4 \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \int \frac {\sqrt {a+i a \tan (c+d x)} \left (-\frac {1}{4} a^2 (80 A-77 i B)-\frac {3}{4} a^2 (20 i A+21 B) \tan (c+d x)\right )}{\tan ^{\frac {5}{2}}(c+d x)} \, dx\\ &=\frac {2 a^2 (80 A-77 i B) \cot ^{\frac {3}{2}}(c+d x) \sqrt {a+i a \tan (c+d x)}}{105 d}-\frac {2 a^2 (10 i A+7 B) \cot ^{\frac {5}{2}}(c+d x) \sqrt {a+i a \tan (c+d x)}}{35 d}-\frac {2 a A \cot ^{\frac {7}{2}}(c+d x) (a+i a \tan (c+d x))^{3/2}}{7 d}+\frac {\left (8 \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \int \frac {\sqrt {a+i a \tan (c+d x)} \left (-\frac {1}{4} a^3 (130 i A+133 B)+\frac {1}{4} a^3 (80 A-77 i B) \tan (c+d x)\right )}{\tan ^{\frac {3}{2}}(c+d x)} \, dx}{105 a}\\ &=\frac {4 a^2 (130 i A+133 B) \sqrt {\cot (c+d x)} \sqrt {a+i a \tan (c+d x)}}{105 d}+\frac {2 a^2 (80 A-77 i B) \cot ^{\frac {3}{2}}(c+d x) \sqrt {a+i a \tan (c+d x)}}{105 d}-\frac {2 a^2 (10 i A+7 B) \cot ^{\frac {5}{2}}(c+d x) \sqrt {a+i a \tan (c+d x)}}{35 d}-\frac {2 a A \cot ^{\frac {7}{2}}(c+d x) (a+i a \tan (c+d x))^{3/2}}{7 d}+\frac {\left (16 \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \int \frac {105 a^4 (A-i B) \sqrt {a+i a \tan (c+d x)}}{4 \sqrt {\tan (c+d x)}} \, dx}{105 a^2}\\ &=\frac {4 a^2 (130 i A+133 B) \sqrt {\cot (c+d x)} \sqrt {a+i a \tan (c+d x)}}{105 d}+\frac {2 a^2 (80 A-77 i B) \cot ^{\frac {3}{2}}(c+d x) \sqrt {a+i a \tan (c+d x)}}{105 d}-\frac {2 a^2 (10 i A+7 B) \cot ^{\frac {5}{2}}(c+d x) \sqrt {a+i a \tan (c+d x)}}{35 d}-\frac {2 a A \cot ^{\frac {7}{2}}(c+d x) (a+i a \tan (c+d x))^{3/2}}{7 d}+\left (4 a^2 (A-i B) \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \int \frac {\sqrt {a+i a \tan (c+d x)}}{\sqrt {\tan (c+d x)}} \, dx\\ &=\frac {4 a^2 (130 i A+133 B) \sqrt {\cot (c+d x)} \sqrt {a+i a \tan (c+d x)}}{105 d}+\frac {2 a^2 (80 A-77 i B) \cot ^{\frac {3}{2}}(c+d x) \sqrt {a+i a \tan (c+d x)}}{105 d}-\frac {2 a^2 (10 i A+7 B) \cot ^{\frac {5}{2}}(c+d x) \sqrt {a+i a \tan (c+d x)}}{35 d}-\frac {2 a A \cot ^{\frac {7}{2}}(c+d x) (a+i a \tan (c+d x))^{3/2}}{7 d}-\frac {\left (8 i a^4 (A-i B) \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \text {Subst}\left (\int \frac {1}{-i a-2 a^2 x^2} \, dx,x,\frac {\sqrt {\tan (c+d x)}}{\sqrt {a+i a \tan (c+d x)}}\right )}{d}\\ &=-\frac {(4+4 i) a^{5/2} (i A+B) \tanh ^{-1}\left (\frac {(1+i) \sqrt {a} \sqrt {\tan (c+d x)}}{\sqrt {a+i a \tan (c+d x)}}\right ) \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}}{d}+\frac {4 a^2 (130 i A+133 B) \sqrt {\cot (c+d x)} \sqrt {a+i a \tan (c+d x)}}{105 d}+\frac {2 a^2 (80 A-77 i B) \cot ^{\frac {3}{2}}(c+d x) \sqrt {a+i a \tan (c+d x)}}{105 d}-\frac {2 a^2 (10 i A+7 B) \cot ^{\frac {5}{2}}(c+d x) \sqrt {a+i a \tan (c+d x)}}{35 d}-\frac {2 a A \cot ^{\frac {7}{2}}(c+d x) (a+i a \tan (c+d x))^{3/2}}{7 d}\\ \end {align*}
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Mathematica [A]
time = 5.37, size = 332, normalized size = 1.32 \begin {gather*} \frac {\left (-4 i \sqrt {2} (A-i B) e^{-3 i (c+d x)} \sqrt {-1+e^{2 i (c+d x)}} \sqrt {\frac {e^{i (c+d x)}}{1+e^{2 i (c+d x)}}} \sqrt {\frac {i \left (1+e^{2 i (c+d x)}\right )}{-1+e^{2 i (c+d x)}}} \tanh ^{-1}\left (\frac {e^{i (c+d x)}}{\sqrt {-1+e^{2 i (c+d x)}}}\right )-\frac {\sqrt {\cot (c+d x)} \csc ^3(c+d x) \sqrt {\sec (c+d x)} (\cos (2 c)-i \sin (2 c)) ((-35 A+77 i B) \cos (c+d x)+(95 A-77 i B) \cos (3 (c+d x))+2 (-215 i A-245 B+(305 i A+287 B) \cos (2 (c+d x))) \sin (c+d x))}{210 (\cos (d x)+i \sin (d x))^2}\right ) (a+i a \tan (c+d x))^{5/2} (A+B \tan (c+d x))}{d \sec ^{\frac {7}{2}}(c+d x) (A \cos (c+d x)+B \sin (c+d x))} \end {gather*}
Antiderivative was successfully verified.
[In]
Integrate[Cot[c + d*x]^(9/2)*(a + I*a*Tan[c + d*x])^(5/2)*(A + B*Tan[c + d*x]),x]
[Out]
((((-4*I)*Sqrt[2]*(A - I*B)*Sqrt[-1 + E^((2*I)*(c + d*x))]*Sqrt[E^(I*(c + d*x))/(1 + E^((2*I)*(c + d*x)))]*Sqr
t[(I*(1 + E^((2*I)*(c + d*x))))/(-1 + E^((2*I)*(c + d*x)))]*ArcTanh[E^(I*(c + d*x))/Sqrt[-1 + E^((2*I)*(c + d*
x))]])/E^((3*I)*(c + d*x)) - (Sqrt[Cot[c + d*x]]*Csc[c + d*x]^3*Sqrt[Sec[c + d*x]]*(Cos[2*c] - I*Sin[2*c])*((-
35*A + (77*I)*B)*Cos[c + d*x] + (95*A - (77*I)*B)*Cos[3*(c + d*x)] + 2*((-215*I)*A - 245*B + ((305*I)*A + 287*
B)*Cos[2*(c + d*x)])*Sin[c + d*x]))/(210*(Cos[d*x] + I*Sin[d*x])^2))*(a + I*a*Tan[c + d*x])^(5/2)*(A + B*Tan[c
+ d*x]))/(d*Sec[c + d*x]^(7/2)*(A*Cos[c + d*x] + B*Sin[c + d*x]))
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Maple [B] Both result and optimal contain complex but leaf count of result is larger than twice
the leaf count of optimal. 3125 vs. \(2 (206 ) = 412\).
time = 68.29, size = 3126, normalized size = 12.45
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\(3126\) |
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Verification of antiderivative is not currently implemented for this CAS.
[In]
int(cot(d*x+c)^(9/2)*(a+I*a*tan(d*x+c))^(5/2)*(A+B*tan(d*x+c)),x,method=_RETURNVERBOSE)
[Out]
-1/105/d*a^2*2^(1/2)*(420*A*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(d*x+c)^4*arctan(((-1+cos(d*x+c))/sin(d*x+c)
)^(1/2)*2^(1/2)+1)+420*A*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(d*x+c)^4*arctan(((-1+cos(d*x+c))/sin(d*x+c))^(
1/2)*2^(1/2)-1)+210*A*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(d*x+c)^4*ln(-(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*
2^(1/2)*sin(d*x+c)-sin(d*x+c)-cos(d*x+c)+1)/(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)*sin(d*x+c)+sin(d*x+c)+
cos(d*x+c)-1))+420*B*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(d*x+c)^4*arctan(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)
*2^(1/2)+1)+420*B*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(d*x+c)^4*arctan(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^
(1/2)-1)+210*B*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(d*x+c)^4*ln(-(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)
*sin(d*x+c)+sin(d*x+c)+cos(d*x+c)-1)/(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)*sin(d*x+c)-sin(d*x+c)-cos(d*x
+c)+1))+210*I*A*ln(-(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)*sin(d*x+c)+sin(d*x+c)+cos(d*x+c)-1)/(((-1+cos(
d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)*sin(d*x+c)-sin(d*x+c)-cos(d*x+c)+1))*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(
d*x+c)^4+420*I*A*arctan(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)+1)*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(d
*x+c)^4+420*I*A*arctan(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)-1)*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(d*
x+c)^4-420*I*B*arctan(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)+1)*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(d*x
+c)^4-420*I*B*arctan(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)-1)*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(d*x+
c)^4-210*I*B*ln(-(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)*sin(d*x+c)-sin(d*x+c)-cos(d*x+c)+1)/(((-1+cos(d*x
+c))/sin(d*x+c))^(1/2)*2^(1/2)*sin(d*x+c)+sin(d*x+c)+cos(d*x+c)-1))*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(d*x
+c)^4+400*I*A*2^(1/2)*cos(d*x+c)^3*sin(d*x+c)-305*I*A*2^(1/2)*cos(d*x+c)^2*sin(d*x+c)-420*I*A*ln(-(((-1+cos(d*
x+c))/sin(d*x+c))^(1/2)*2^(1/2)*sin(d*x+c)+sin(d*x+c)+cos(d*x+c)-1)/(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2
)*sin(d*x+c)-sin(d*x+c)-cos(d*x+c)+1))*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(d*x+c)^2-840*I*A*arctan(((-1+cos
(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)+1)*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(d*x+c)^2-840*I*A*arctan(((-1+cos(
d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)-1)*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(d*x+c)^2+840*I*B*arctan(((-1+cos(d
*x+c))/sin(d*x+c))^(1/2)*2^(1/2)+1)*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(d*x+c)^2+840*I*B*arctan(((-1+cos(d*
x+c))/sin(d*x+c))^(1/2)*2^(1/2)-1)*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(d*x+c)^2+420*I*B*ln(-(((-1+cos(d*x+c
))/sin(d*x+c))^(1/2)*2^(1/2)*sin(d*x+c)-sin(d*x+c)-cos(d*x+c)+1)/(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)*s
in(d*x+c)+sin(d*x+c)+cos(d*x+c)-1))*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(d*x+c)^2-340*I*A*2^(1/2)*cos(d*x+c)
*sin(d*x+c)+260*A*2^(1/2)-287*B*cos(d*x+c)^2*sin(d*x+c)*2^(1/2)-266*I*B*2^(1/2)+364*B*cos(d*x+c)^3*sin(d*x+c)*
2^(1/2)-95*A*cos(d*x+c)^3*2^(1/2)+80*A*cos(d*x+c)*2^(1/2)-840*A*cos(d*x+c)^2*((-1+cos(d*x+c))/sin(d*x+c))^(1/2
)*arctan(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)+1)+400*A*cos(d*x+c)^4*2^(1/2)+420*A*((-1+cos(d*x+c))/sin(d
*x+c))^(1/2)*arctan(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)+1)+420*A*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*arc
tan(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)-1)+420*B*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*arctan(((-1+cos(d*x
+c))/sin(d*x+c))^(1/2)*2^(1/2)+1)+420*B*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*arctan(((-1+cos(d*x+c))/sin(d*x+c))
^(1/2)*2^(1/2)-1)-420*A*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(d*x+c)^2*ln(-(((-1+cos(d*x+c))/sin(d*x+c))^(1/2
)*2^(1/2)*sin(d*x+c)-sin(d*x+c)-cos(d*x+c)+1)/(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)*sin(d*x+c)+sin(d*x+c
)+cos(d*x+c)-1))-420*B*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*cos(d*x+c)^2*ln(-(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)
*2^(1/2)*sin(d*x+c)+sin(d*x+c)+cos(d*x+c)-1)/(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)*sin(d*x+c)-sin(d*x+c)
-cos(d*x+c)+1))-343*B*2^(1/2)*cos(d*x+c)*sin(d*x+c)+210*A*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*ln(-(((-1+cos(d*x
+c))/sin(d*x+c))^(1/2)*2^(1/2)*sin(d*x+c)-sin(d*x+c)-cos(d*x+c)+1)/(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)
*sin(d*x+c)+sin(d*x+c)+cos(d*x+c)-1))+210*B*((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*ln(-(((-1+cos(d*x+c))/sin(d*x+c
))^(1/2)*2^(1/2)*sin(d*x+c)+sin(d*x+c)+cos(d*x+c)-1)/(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)*sin(d*x+c)-si
n(d*x+c)-cos(d*x+c)+1))+266*2^(1/2)*B*sin(d*x+c)-645*A*2^(1/2)*cos(d*x+c)^2-840*A*cos(d*x+c)^2*((-1+cos(d*x+c)
)/sin(d*x+c))^(1/2)*arctan(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)-1)-840*B*cos(d*x+c)^2*((-1+cos(d*x+c))/s
in(d*x+c))^(1/2)*arctan(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)+1)-840*B*cos(d*x+c)^2*((-1+cos(d*x+c))/sin(
d*x+c))^(1/2)*arctan(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)-1)-364*I*B*2^(1/2)*cos(d*x+c)^4+77*I*B*2^(1/2)
*cos(d*x+c)^3+630*I*B*2^(1/2)*cos(d*x+c)^2+260*I*A*2^(1/2)*sin(d*x+c)+210*I*A*ln(-(((-1+cos(d*x+c))/sin(d*x+c)
)^(1/2)*2^(1/2)*sin(d*x+c)+sin(d*x+c)+cos(d*x+c)-1)/(((-1+cos(d*x+c))/sin(d*x+c))^(1/2)*2^(1/2)*sin(d*x+c)-sin
(d*x+c)-cos(d*x+c)+1))*((-1+cos(d*x+c))/sin(d*x...
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Maxima [B] Both result and optimal contain complex but leaf count of result is larger than
twice the leaf count of optimal. 4087 vs. \(2 (193) = 386\).
time = 2.13, size = 4087, normalized size = 16.28 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(cot(d*x+c)^(9/2)*(a+I*a*tan(d*x+c))^(5/2)*(A+B*tan(d*x+c)),x, algorithm="maxima")
[Out]
-1/105*(sqrt(cos(2*d*x + 2*c)^2 + sin(2*d*x + 2*c)^2 - 2*cos(2*d*x + 2*c) + 1)*(3*(140*(-(I - 1)*A - (I + 1)*B
)*a^2*cos(7*d*x + 7*c) + 140*((I - 1)*A + (2*I + 2)*B)*a^2*cos(5*d*x + 5*c) + 21*(-(4*I - 4)*A - (9*I + 9)*B)*
a^2*cos(3*d*x + 3*c) + ((4*I - 4)*A + (49*I + 49)*B)*a^2*cos(d*x + c) + 140*((I + 1)*A - (I - 1)*B)*a^2*sin(7*
d*x + 7*c) + 140*(-(I + 1)*A + (2*I - 2)*B)*a^2*sin(5*d*x + 5*c) + 21*((4*I + 4)*A - (9*I - 9)*B)*a^2*sin(3*d*
x + 3*c) + (-(4*I + 4)*A + (49*I - 49)*B)*a^2*sin(d*x + c))*cos(7/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c)
- 1)) + 4*(((65*I - 65)*A + (56*I + 56)*B)*a^2*cos(d*x + c) + (-(65*I + 65)*A + (56*I - 56)*B)*a^2*sin(d*x +
c) + (((65*I - 65)*A + (56*I + 56)*B)*a^2*cos(d*x + c) + (-(65*I + 65)*A + (56*I - 56)*B)*a^2*sin(d*x + c))*co
s(2*d*x + 2*c)^2 + (((65*I - 65)*A + (56*I + 56)*B)*a^2*cos(d*x + c) + (-(65*I + 65)*A + (56*I - 56)*B)*a^2*si
n(d*x + c))*sin(2*d*x + 2*c)^2 + 105*((-(I - 1)*A - (I + 1)*B)*a^2*cos(2*d*x + 2*c)^2 + (-(I - 1)*A - (I + 1)*
B)*a^2*sin(2*d*x + 2*c)^2 + 2*((I - 1)*A + (I + 1)*B)*a^2*cos(2*d*x + 2*c) + (-(I - 1)*A - (I + 1)*B)*a^2)*cos
(3*d*x + 3*c) + 2*((-(65*I - 65)*A - (56*I + 56)*B)*a^2*cos(d*x + c) + ((65*I + 65)*A - (56*I - 56)*B)*a^2*sin
(d*x + c))*cos(2*d*x + 2*c) + 105*(((I + 1)*A - (I - 1)*B)*a^2*cos(2*d*x + 2*c)^2 + ((I + 1)*A - (I - 1)*B)*a^
2*sin(2*d*x + 2*c)^2 + 2*(-(I + 1)*A + (I - 1)*B)*a^2*cos(2*d*x + 2*c) + ((I + 1)*A - (I - 1)*B)*a^2)*sin(3*d*
x + 3*c))*cos(3/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) - 1)) + 3*(140*(-(I + 1)*A + (I - 1)*B)*a^2*cos(7
*d*x + 7*c) + 140*((I + 1)*A - (2*I - 2)*B)*a^2*cos(5*d*x + 5*c) + 21*(-(4*I + 4)*A + (9*I - 9)*B)*a^2*cos(3*d
*x + 3*c) + ((4*I + 4)*A - (49*I - 49)*B)*a^2*cos(d*x + c) + 140*(-(I - 1)*A - (I + 1)*B)*a^2*sin(7*d*x + 7*c)
+ 140*((I - 1)*A + (2*I + 2)*B)*a^2*sin(5*d*x + 5*c) + 21*(-(4*I - 4)*A - (9*I + 9)*B)*a^2*sin(3*d*x + 3*c) +
((4*I - 4)*A + (49*I + 49)*B)*a^2*sin(d*x + c))*sin(7/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) - 1)) + 4*
(((65*I + 65)*A - (56*I - 56)*B)*a^2*cos(d*x + c) + ((65*I - 65)*A + (56*I + 56)*B)*a^2*sin(d*x + c) + (((65*I
+ 65)*A - (56*I - 56)*B)*a^2*cos(d*x + c) + ((65*I - 65)*A + (56*I + 56)*B)*a^2*sin(d*x + c))*cos(2*d*x + 2*c
)^2 + (((65*I + 65)*A - (56*I - 56)*B)*a^2*cos(d*x + c) + ((65*I - 65)*A + (56*I + 56)*B)*a^2*sin(d*x + c))*si
n(2*d*x + 2*c)^2 + 105*((-(I + 1)*A + (I - 1)*B)*a^2*cos(2*d*x + 2*c)^2 + (-(I + 1)*A + (I - 1)*B)*a^2*sin(2*d
*x + 2*c)^2 + 2*((I + 1)*A - (I - 1)*B)*a^2*cos(2*d*x + 2*c) + (-(I + 1)*A + (I - 1)*B)*a^2)*cos(3*d*x + 3*c)
+ 2*((-(65*I + 65)*A + (56*I - 56)*B)*a^2*cos(d*x + c) + (-(65*I - 65)*A - (56*I + 56)*B)*a^2*sin(d*x + c))*co
s(2*d*x + 2*c) + 105*((-(I - 1)*A - (I + 1)*B)*a^2*cos(2*d*x + 2*c)^2 + (-(I - 1)*A - (I + 1)*B)*a^2*sin(2*d*x
+ 2*c)^2 + 2*((I - 1)*A + (I + 1)*B)*a^2*cos(2*d*x + 2*c) + (-(I - 1)*A - (I + 1)*B)*a^2)*sin(3*d*x + 3*c))*s
in(3/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) - 1)))*sqrt(a) + 210*(2*((-(I + 1)*A + (I - 1)*B)*a^2*cos(2*
d*x + 2*c)^4 + (-(I + 1)*A + (I - 1)*B)*a^2*sin(2*d*x + 2*c)^4 + 4*((I + 1)*A - (I - 1)*B)*a^2*cos(2*d*x + 2*c
)^3 + 6*(-(I + 1)*A + (I - 1)*B)*a^2*cos(2*d*x + 2*c)^2 + 4*((I + 1)*A - (I - 1)*B)*a^2*cos(2*d*x + 2*c) + (-(
I + 1)*A + (I - 1)*B)*a^2 + 2*((-(I + 1)*A + (I - 1)*B)*a^2*cos(2*d*x + 2*c)^2 + 2*((I + 1)*A - (I - 1)*B)*a^2
*cos(2*d*x + 2*c) + (-(I + 1)*A + (I - 1)*B)*a^2)*sin(2*d*x + 2*c)^2)*arctan2(2*(cos(2*d*x + 2*c)^2 + sin(2*d*
x + 2*c)^2 - 2*cos(2*d*x + 2*c) + 1)^(1/4)*sin(1/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) - 1)) + 2*sin(d*
x + c), 2*(cos(2*d*x + 2*c)^2 + sin(2*d*x + 2*c)^2 - 2*cos(2*d*x + 2*c) + 1)^(1/4)*cos(1/2*arctan2(sin(2*d*x +
2*c), cos(2*d*x + 2*c) - 1)) + 2*cos(d*x + c)) + (((I - 1)*A + (I + 1)*B)*a^2*cos(2*d*x + 2*c)^4 + ((I - 1)*A
+ (I + 1)*B)*a^2*sin(2*d*x + 2*c)^4 + 4*(-(I - 1)*A - (I + 1)*B)*a^2*cos(2*d*x + 2*c)^3 + 6*((I - 1)*A + (I +
1)*B)*a^2*cos(2*d*x + 2*c)^2 + 4*(-(I - 1)*A - (I + 1)*B)*a^2*cos(2*d*x + 2*c) + ((I - 1)*A + (I + 1)*B)*a^2
+ 2*(((I - 1)*A + (I + 1)*B)*a^2*cos(2*d*x + 2*c)^2 + 2*(-(I - 1)*A - (I + 1)*B)*a^2*cos(2*d*x + 2*c) + ((I -
1)*A + (I + 1)*B)*a^2)*sin(2*d*x + 2*c)^2)*log(4*cos(d*x + c)^2 + 4*sin(d*x + c)^2 + 4*sqrt(cos(2*d*x + 2*c)^2
+ sin(2*d*x + 2*c)^2 - 2*cos(2*d*x + 2*c) + 1)*(cos(1/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) - 1))^2 +
sin(1/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) - 1))^2) + 8*(cos(2*d*x + 2*c)^2 + sin(2*d*x + 2*c)^2 - 2*c
os(2*d*x + 2*c) + 1)^(1/4)*(cos(d*x + c)*cos(1/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) - 1)) + sin(d*x +
c)*sin(1/2*arctan2(sin(2*d*x + 2*c), cos(2*d*x + 2*c) - 1)))))*(cos(2*d*x + 2*c)^2 + sin(2*d*x + 2*c)^2 - 2*co
s(2*d*x + 2*c) + 1)^(1/4)*sqrt(a) + (((-(608*I - 608)*A - (581*I + 581)*B)*a^2*cos(d*x + c) + ((608*I + 608)*A
- (581*I - 581)*B)*a^2*sin(d*x + c) + ((-(608*I - 608)*A - (581*I + 581)*B)*a^2*cos(d*x + c) + ((608*I + 608)
*A - (581*I - 581)*B)*a^2*sin(d*x + c))*cos(2*d*x + 2*c)^2 + ((-(608*I - 608)*A - (581*I + 581)*B)*a^2*cos(d*x
+ c) + ((608*I + 608)*A - (581*I - 581)*B)*a^2...
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Fricas [B] Both result and optimal contain complex but leaf count of result is larger than twice
the leaf count of optimal. 577 vs. \(2 (193) = 386\).
time = 1.89, size = 577, normalized size = 2.30 \begin {gather*} \frac {2 \, {\left (105 \, \sqrt {2} \sqrt {-\frac {{\left (i \, A^{2} + 2 \, A B - i \, B^{2}\right )} a^{5}}{d^{2}}} {\left (d e^{\left (6 i \, d x + 6 i \, c\right )} - 3 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 3 \, d e^{\left (2 i \, d x + 2 i \, c\right )} - d\right )} \log \left (\frac {4 \, {\left ({\left (A - i \, B\right )} a^{3} e^{\left (i \, d x + i \, c\right )} + \sqrt {-\frac {{\left (i \, A^{2} + 2 \, A B - i \, B^{2}\right )} a^{5}}{d^{2}}} {\left (d e^{\left (2 i \, d x + 2 i \, c\right )} - d\right )} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} \sqrt {\frac {i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} - 1}}\right )} e^{\left (-i \, d x - i \, c\right )}}{{\left (-i \, A - B\right )} a^{2}}\right ) - 105 \, \sqrt {2} \sqrt {-\frac {{\left (i \, A^{2} + 2 \, A B - i \, B^{2}\right )} a^{5}}{d^{2}}} {\left (d e^{\left (6 i \, d x + 6 i \, c\right )} - 3 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 3 \, d e^{\left (2 i \, d x + 2 i \, c\right )} - d\right )} \log \left (\frac {4 \, {\left ({\left (A - i \, B\right )} a^{3} e^{\left (i \, d x + i \, c\right )} - \sqrt {-\frac {{\left (i \, A^{2} + 2 \, A B - i \, B^{2}\right )} a^{5}}{d^{2}}} {\left (d e^{\left (2 i \, d x + 2 i \, c\right )} - d\right )} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} \sqrt {\frac {i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} - 1}}\right )} e^{\left (-i \, d x - i \, c\right )}}{{\left (-i \, A - B\right )} a^{2}}\right ) - 2 \, \sqrt {2} {\left (2 \, {\left (-100 i \, A - 91 \, B\right )} a^{2} e^{\left (7 i \, d x + 7 i \, c\right )} + 7 \, {\left (55 i \, A + 61 \, B\right )} a^{2} e^{\left (5 i \, d x + 5 i \, c\right )} + 350 \, {\left (-i \, A - B\right )} a^{2} e^{\left (3 i \, d x + 3 i \, c\right )} + 105 \, {\left (i \, A + B\right )} a^{2} e^{\left (i \, d x + i \, c\right )}\right )} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} \sqrt {\frac {i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} - 1}}\right )}}{105 \, {\left (d e^{\left (6 i \, d x + 6 i \, c\right )} - 3 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 3 \, d e^{\left (2 i \, d x + 2 i \, c\right )} - d\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(cot(d*x+c)^(9/2)*(a+I*a*tan(d*x+c))^(5/2)*(A+B*tan(d*x+c)),x, algorithm="fricas")
[Out]
2/105*(105*sqrt(2)*sqrt(-(I*A^2 + 2*A*B - I*B^2)*a^5/d^2)*(d*e^(6*I*d*x + 6*I*c) - 3*d*e^(4*I*d*x + 4*I*c) + 3
*d*e^(2*I*d*x + 2*I*c) - d)*log(4*((A - I*B)*a^3*e^(I*d*x + I*c) + sqrt(-(I*A^2 + 2*A*B - I*B^2)*a^5/d^2)*(d*e
^(2*I*d*x + 2*I*c) - d)*sqrt(a/(e^(2*I*d*x + 2*I*c) + 1))*sqrt((I*e^(2*I*d*x + 2*I*c) + I)/(e^(2*I*d*x + 2*I*c
) - 1)))*e^(-I*d*x - I*c)/((-I*A - B)*a^2)) - 105*sqrt(2)*sqrt(-(I*A^2 + 2*A*B - I*B^2)*a^5/d^2)*(d*e^(6*I*d*x
+ 6*I*c) - 3*d*e^(4*I*d*x + 4*I*c) + 3*d*e^(2*I*d*x + 2*I*c) - d)*log(4*((A - I*B)*a^3*e^(I*d*x + I*c) - sqrt
(-(I*A^2 + 2*A*B - I*B^2)*a^5/d^2)*(d*e^(2*I*d*x + 2*I*c) - d)*sqrt(a/(e^(2*I*d*x + 2*I*c) + 1))*sqrt((I*e^(2*
I*d*x + 2*I*c) + I)/(e^(2*I*d*x + 2*I*c) - 1)))*e^(-I*d*x - I*c)/((-I*A - B)*a^2)) - 2*sqrt(2)*(2*(-100*I*A -
91*B)*a^2*e^(7*I*d*x + 7*I*c) + 7*(55*I*A + 61*B)*a^2*e^(5*I*d*x + 5*I*c) + 350*(-I*A - B)*a^2*e^(3*I*d*x + 3*
I*c) + 105*(I*A + B)*a^2*e^(I*d*x + I*c))*sqrt(a/(e^(2*I*d*x + 2*I*c) + 1))*sqrt((I*e^(2*I*d*x + 2*I*c) + I)/(
e^(2*I*d*x + 2*I*c) - 1)))/(d*e^(6*I*d*x + 6*I*c) - 3*d*e^(4*I*d*x + 4*I*c) + 3*d*e^(2*I*d*x + 2*I*c) - d)
________________________________________________________________________________________
Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(cot(d*x+c)**(9/2)*(a+I*a*tan(d*x+c))**(5/2)*(A+B*tan(d*x+c)),x)
[Out]
Timed out
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(cot(d*x+c)^(9/2)*(a+I*a*tan(d*x+c))^(5/2)*(A+B*tan(d*x+c)),x, algorithm="giac")
[Out]
integrate((B*tan(d*x + c) + A)*(I*a*tan(d*x + c) + a)^(5/2)*cot(d*x + c)^(9/2), x)
________________________________________________________________________________________
Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int {\mathrm {cot}\left (c+d\,x\right )}^{9/2}\,\left (A+B\,\mathrm {tan}\left (c+d\,x\right )\right )\,{\left (a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}\right )}^{5/2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
int(cot(c + d*x)^(9/2)*(A + B*tan(c + d*x))*(a + a*tan(c + d*x)*1i)^(5/2),x)
[Out]
int(cot(c + d*x)^(9/2)*(A + B*tan(c + d*x))*(a + a*tan(c + d*x)*1i)^(5/2), x)
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